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Gauss' principle

The Gauss' principle states that the accelerations \(\bar{a}_k\) of \(n\) solids subject to constraints, deviate the least from the accelerations \(a_k\) that the solids would have had without the constraints. Where, the deviation of \(\bar{a}_k\) from \(a_k\) is measured using the following metric

\[ (\bar{a}_k-a_k)^TM_k(\bar{a}_k - a_k). \]

Hence, for \(n\) solids we have

\[ \minimize{\bar{a}_1,\dots\bar{a}_n} V(\bar{a}_1,\dots\bar{a}_n) = \sum_{k=1}^{n}(\bar{a}_k-a_k)^TM_k(\bar{a}_k - a_k), \]

where

\[ M_k = \begin{bmatrix}m_kI & 0\\ 0 & \mathbb{I}_k\end{bmatrix}, \]
  • \(m_k\) - mass of the \(k\)-th solid
  • \(\mathbb{I}_k\) - inertia (about the center of mass) of the \(k\)-th solid
  • \(I \in \mathbb{R}^{3 \times 3}\) - identity matrix.

All quantities are expressed in a common frame of reference. Define

\[\begin{align} \bar{a}_k &= J_k\ddot{q} + \dot{J}_k\dot{q} \nonumber \\ a_k &= M_k^{-1}(w_k - n_k) \leftarrow \mbox{Newton-Euler equations}. \nonumber \end{align}\]

The term \(n_k\) is given by

\[ n_k = \begin{bmatrix} 0 \\ \omega_k\times\mathbb{I}_k\omega_k \end{bmatrix}, \]

while \(w_k = (f_k,t_k)\) denotes the external wrench applied to the \(k\)-th solid (\(f_k\) is the force applied at its center of mass). Substituting \(\bar{a}_k\) and \(a_k\) from above in \(V\) leads to

\[\begin{align} V(\ddot{q}) &= \sum_{k=1}^{n}(J_k\ddot{q} + \dot{J}_k\dot{q}-M_k^{-1}(w_k - n_k))^TM_k % (J_k\ddot{q} + \dot{J}_k\dot{q}-M_k^{-1}(w_k - n_k)) \nonumber \\ &:= \sum_{k=1}^{n}\left\{\ddot{q}^TJ_k^{T}M_kJ_k\ddot{q} + 2\ddot{q}^TJ_k^{T}M_k (\dot{J}_k\dot{q} - M_k^{-1}(w_k - n_k))\right\}, \nonumber \end{align}\]

where terms independent of \(\ddot{q}\) were dropped.

\[ \frac{\partial V}{\partial \ddot{q}} = \sum_{k=1}^{n}\left\{J_k^{T}M_kJ_k\ddot{q} + J_k^{T}M_k\dot{J}_k\dot{q} - J_k^{T}(w_k - n_k))\right\} = 0. \]

After rearranging we obtain the equations of motion \(H(q)\ddot{q} + h(q, \dot{q}) = J^Tw\):

\[ \underbrace{\sum_{k=1}^{n}J_k^{T}M_kJ_k}_{H(q)}\ddot{q} + \underbrace{\sum_{k=1}^{n}J_k^{T}(M_k\dot{J}_k\dot{q} +n_k)}_{h(q, \dot{q})} = \underbrace{\sum_{k=1}^{n}J_k^{T}}_{J^T}w_k, \quad w = (w_1, \dots, w_n). \]